9r^2+48r+64=0

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Solution for 9r^2+48r+64=0 equation: 



9r^2+48r+64=0

a = 9; b = 48; c = +64;
Δ = b2-4ac
Δ = 482-4·9·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-48}{18}=-2+2/3$

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